문제 설명
https://www.acmicpc.net/problem/1012
풀이과정
DFS나 BFS로 풀이한다.
정답코드
import java.io.*;
import java.util.*;
public class Main {
static int[] dy = {-1, 1, 0, 0};
static int[] dx = {0, 0, -1, 1};
static int[][] board;
static boolean[][] visited;
static int N, M, K;
static int result = 0;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
int T = Integer.parseInt(br.readLine());
StringTokenizer st;
for (int i = 0; i < T; i++) {
st = new StringTokenizer(br.readLine());
M = Integer.parseInt(st.nextToken());
N = Integer.parseInt(st.nextToken());
K = Integer.parseInt(st.nextToken());
board = new int[N][M];
visited = new boolean[N][M];
result = 0;
for (int j = 0; j < K; j++) {
st = new StringTokenizer(br.readLine());
int x = Integer.parseInt(st.nextToken());
int y = Integer.parseInt(st.nextToken());
board[y][x] = 1;
}
for (int j = 0; j < N; j++) {
for (int k = 0; k < M; k++) {
if (board[j][k] == 1 && !visited[j][k]) {
dfs(j, k);
result++;
}
}
}
bw.write(result + "\n");
}
bw.flush();
}
public static void dfs(int y, int x) {
if (visited[y][x]) {
return;
}
visited[y][x] = true;
for (int i = 0; i < 4; i++) {
int ny = y + dy[i];
int nx = x + dx[i];
if (ny >= 0 && ny < N && nx >= 0 && nx < M) {
if (board[ny][nx] == 1 && !visited[ny][nx]) {
dfs(ny, nx);
}
}
}
}
}